detect if variable is of sympy type


I have a variable which may or may not be a sympy class. I want to convert it to a float but I’m having trouble doing this in a general manner:

$ python Python 2.7.3 (default, Dec 18 2014, 19:10:20) [GCC 4.6.3] on linux2 >>> import sympy >>> x = sympy.sqrt(2) >>> type(x) <class 'sympy.core.power.Pow'> >>> y = 1 + x >>> type(y) <class 'sympy.core.add.Add'> >>> z = 3 * x >>> type(z) <class 'sympy.core.mul.Mul'> >>> if isinstance(z, sympy.core): ... z = z.evalf(50) # 50 dp ... Traceback (most recent call last): File "<stdin>", line 1, in <module> TypeError: isinstance() arg 2 must be a class, type, or tuple of classes and types

I will be testing x, y, z to convert into a float. note that I can't just run evalf() on x, y and z without checking because they might be integers or floats already and this would raise an exception.

<hr />

sympy.sympify() unfortunately does not convert to float. if it did then that would be the ideal solution to my problem:

>>> sympy.sympify(z) 3*sqrt(2) >>> type(sympy.sympify(z)) <class 'sympy.core.mul.Mul'>

All sympy objects inherit from sympy.Basic. To evaluate an sympy expression numerically, just use .n()

In [1]: import sympy In [2]: x = sympy.sqrt(2) In [3]: x Out[3]: sqrt(2) In [4]: x.n() Out[4]: 1.41421356237310 In [5]: if (isinstance(x, sympy.Basic)): ...: print(x.n()) ...: 1.41421356237310

heh, at the end of the day, it turns out you can just convert a sympy object to float using python's native float conversion function! don't know why i didn't try this straight away...

>>> import sympy >>> x = sympy.sqrt(2) >>> float(x) 1.4142135623730951

i will use this since it works even if x is a python int or already a python float



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