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How to organize a javascript object that contains store hours?

Question:

If I have an object with store information that looks like this.

storeHours: 0: day: Sunday Open: 9:00am close: 6:00pm 0: day: Monday Open: 8:00am close: 10:00pm 0: day: Tuesday Open: 8:00am close: 10:00pm 0: day: Wednesday Open: 8:00am close: 10:00pm 0: day: Thursday Open: 8:00am close: 10:00pm 0: day: Friday Open: 8:00am close: 10:00pm 0: day: Saturday Open: 9:00am close: 6:00pm

What function should I write to get output that would give me

simplestoreHours: 0: Days: Monday-Friday open: 8:00am close: 6:00pm 1: Days: Saturday-Sunday open: 9:00am close: 6:00pm

Also all the times are formatted momentjs objects so it is possible to use momentjs.

My initial thought is to do a loop and have each element checked against each other. If the open and closing times are the same then just connect the days, but I don't think this very clever.

Answer1:

reduce Array method can help you.

<ol><li>we have to iterate over initial dates object.</li> <li>group days and working hours into 2 helper arrays by key. i used concatenated open and close time</li> <li>keep open and close time in ranges sub array </li> <li>as we are not sure initial array sorted by day of week i've added day index into days grouped array.</li> <li>

on last iteration lets come through ranges we have and find days with range key, sort it, create Days property as concationation first and last sorted days array and save combined object.

var groupedObject = obj.reduce(function (memo, item, i, array) { var key = item.open+item.close; memo.ranges[key] = memo.ranges[key] || {}; memo.days[key] = memo.days[key] || []; memo.ranges[key] = { open: item.open, close: item.open }; memo.days[key].push({ index: ['mon', 'tue', 'wed', 'thu', 'fri', 'sat', 'sun'].indexOf(item.day), name: item.day }) if (i == array.length-1 ) { for (var key in memo.ranges) { if (memo.ranges.hasOwnProperty(key)) { memo.days[key].sort(function(a,b) { return a.index - b.index }); memo.grouped.push({ Days: [ memo.days[key][0].name, memo.days[key][memo.days[key].length-1 ].name ].join('-'), open: memo.ranges[key].open, close: memo.ranges[key].close }); } } } return memo }, { ranges: {}, days: {}, grouped: [] }); console.log(groupedObject.grouped); </li> </ol>

thats it)

Answer2:

You could do it this way:

var storeHours = [ {day: 'Sunday', open: '9:00am', close: '6:00pm' }, {day: 'Monday', open: '8:00am', close: '10:00pm' }, {day: 'Tuesday', open: '8:00am', close: '10:00pm' }, {day: 'Wednesday', open: '8:00am', close: '10:00pm' }, {day: 'Thursday', open: '8:00am', close: '10:00pm' }, {day: 'Friday', open: '8:00am', close: '10:00pm' }, {day: 'Saturday', open: '9:00am', close: '6:00pm' } ]; function sort() { var daysSorted = []; for (var dayCounter = 0, length = storeHours.length; dayCounter < length; dayCounter++) { var open = storeHours[dayCounter].open, close = storeHours[dayCounter].close, name = storeHours[dayCounter].day, found = false; for (var sortedDayCounter = 0, lengthSorted = daysSorted.length; sortedDayCounter < lengthSorted; sortedDayCounter++) { var sortedOpen = daysSorted[sortedDayCounter].open, sortedClose = daysSorted[sortedDayCounter].close; if (sortedOpen === open && sortedClose == close) { daysSorted[sortedDayCounter].day += ', ' + name; found = true; } }; if (!found) { daysSorted.push(storeHours[dayCounter]); } }; return daysSorted; } console.log(sort());

Anyway, I recommend that you consider open and close dates as Date types, rather than strings.

Hope this helps,

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