Ruby on Rails: Simple way to select all records of a nested model?


Just curious, I spent an embarrassing amount of time trying to get an array of all the records in a nested model. I just want to make sure there is not a better way.

Here is the setup:

I have three models that are nested under each other (Facilities >> Tags >> Inspections), producing code like this for routes.rb:

map.resources :facilities do |facilities| facilities.resources :tags, :has_many => :inspections end

I wanted to get all of the inspections for a facility and here is what my code ended up being:

def facility_inspections @facility = Facility.find(params[:facility_id]) @inspections = [] @facility.tags.each do |tag| tag.inspections.each do |inspection| @inspections << inspection end end end

It works but is this the best way to do this - I think it's cumbersome.


You can use has_many :through association. In your models:

# Facility model has_many :tags has_many :inspections, :through => :tags # Tag model belongs_to :facility has_many :inspections

And you can get all inspections like this:

@inspections = Facility.find(params[:facility_id]).inspections

But if you have HABTM relation between Facility and Tag it will be more complicated and you would have to write some sql manualy, like this:

@inspections = Inspection.all(:joins => "INNER JOIN tags ON tags.id = inspections.tag_id INNER JOIN facilities_tags ON tags.id = facilities_tags.tag_id", :conditions => ["facilities_tags.facility_id = ?", params[:facility_id] )

Of course above code depends on your table structure. If you will show it, then it would be easier to give correct answer :). Hope it helps!


@facility = Facility.find(params[:facility_id], :include => {:tags => :inspections})

This executes one query against the database (your original solution would use many of them), and returns a facility object with all the tag and inspections included. Then you can do something like:

@inspections = @facility.tags.map(&:inspections).flatten


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