How to write a regex expression that replace anchors and links value


My html code has many anchors and links such as :

<script src="/Common/Scripts/jquery-1.4.4.min.js" type="text/javascript"></script> <link href="/Common/Css/UserAdmin.css" rel="stylesheet" type="text/css" /> <a href="/test.php">test</a></li>

I want to change them into:

<script src="http://www.mydomain.com/Common/Scripts/jquery-1.4.4.min.js" type="text/javascript"></script> <link href="http://www.mydomain.com/Common/Css/UserAdmin.css" rel="stylesheet" type="text/css" /> <a href="http://www.mydomain.com/test.php">test</a></li>

ie. add a http://www.mydomain.com before every src and href value, how to achieve this using regex expression. PS: I use PHP language.


Use the following regexp:


and replace with:


The main idea here is to use the lazy operator "+?"

Group1: ([\b]*) 0 or more blanks ... followed by Group2: (src|href) src or href ... followed by Group3: ([\b]*=[\b]*") 0 or more blanks followed by = followed by 0 or more blanks followed by a quote ... followed by Group4: (.+?") any group of characters until the nearest quote

then replace with what has matched Group1 then Group2 then Group3, insert <a href="http://www.mydomain.com" rel="nofollow">http://www.mydomain.com</a>, then what has matched Group4


Don't hurt yourself with regexp if you don't need to.

$search = array('<script src="/', '<link href="/', '<a href="/'); $d = 'http://www.mydomain.com'; $replace = array('<script src="'.$d.'/', '<link href="'.$d.'/', '<a href="'.$d.'/'); str_replace($search, $replace, $s)


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