68620

convert date to Mysql date format php

Question:

I have this date format in my db

19th April 2013

I want to convert it to

2013-04-19

I have used if,else conditions , BUt it becomes too long and complicated .Are there any built in functions ??

Answer1:

Use PHP's date function

date("Y-m-d",strtotime("19th April 2013"));

Answer2:

yes below code to change date format

date("Y-m-d",strtotime("19th April 2013")); to get as 2013-04-19

and for second one

date("Y/m/d",strtotime("17th April 2013")); to get as 2013-04-17

Answer3:

You can still do it via query so you will not have any conversion on PHP side. Since the data type of the column is string, you need to convert it to a valid date using STR_TO_DATE.

SELECT DATE_FORMAT(STR_TO_DATE(columnname, '%D %M %Y'), '%Y-%m-%d') new_format FROM TableName <ul><li><a href="http://www.sqlfiddle.com/#!2/7281e/1" rel="nofollow">SQLFiddle Demo</a></li> </ul>

Answer4:

following PHP code convert the date into desired format

$date = '19th April 2013' echo date('Y-m-d', strtotime($date));

and other formats are as follows

April 22, 2013 date("F d, Y",strtotime($myrow['date'])); Monday, April 22, 2013 date("l, F d, Y",strtotime($myrow['date'])); Apr 22, 2013 date("M d, Y",strtotime($myrow['date'])); 22 April 2013 date("d F Y",strtotime($myrow['date'])); 22 Apr 2013 date("d M Y",strtotime($myrow['date'])); Mon, 22 Apr 2013 date("D, d M Y",strtotime($myrow['date'])); Monday, the 22nd of April, 2013 date("l",strtotime($myrow['date'])) . ", the " . date("jS",strtotime($myrow['date'])) . " of " . date("F, Y",strtotime($myrow['date']));

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