PHP - get data from database compare it to variable and sort by less value


Script should:

<ol><li>Take latitude and logitude from database of each cinema with while()</li> <li>Compare to location of a user</li> <li>Get the output in kilometers</li> <li>Show all of them based on less kilometers</li> </ol>

Everything is solved on the script down below, only number 4 is not implemented.

I have no idea how to compare every item of while() loop and show everything in the ascending order.

<?php $sql = "SELECT DISTINCT * FROM cinemas WHERE city='$city'"; $result = $conn->query($sql); if ($result->num_rows > 0) { // output data of each row while($row = $result->fetch_assoc()) { $lat1 = $_GET['lat']; //latitude of a user $lon1= $_GET['lon']; //longitude of a user $lat2 = $row['latitude']; //latitude of a cinema $lon2 = $row['longitude']; //longitude of a cinema $theta = $lon1 - $lon2; $dist = sin(deg2rad($lat1)) * sin(deg2rad($lat2)) + cos(deg2rad($lat1)) * cos(deg2rad($lat2)) * cos(deg2rad($theta)); $dist = acos($dist); $dist = rad2deg($dist); $miles = $dist * 60 * 1.1515; $unit = $miles * 1.609344; //calculated the distance between them $distance = substr($unit,0,4)." km"; //output of a distance echo $distance; ?> //here is the data about movie <div id="time"><?php echo $row3['showone']; // timing of a movie ?></div> }} ?>

Script out is:

20 km movie information 5 km movie information 45 km movie information 1 km movie information

I need to show them in ascending order.


Use sort() with your distance.

echo sort($distance);


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