Why the id of an object would change depending on the line in the python shell

This questions is just out of curiosity.

While I was reading the python's object model documentation, I decided to experiment a little with the id of a class method and found this behavior:

Python 3.2.2 (default, Sep 4 2011, 09:07:29) [MSC v.1500 64 bit (AMD64)] on win32 Type "copyright", "credits" or "license()" for more information. >>> class A(): def a(self): pass >>> id(A().a) 54107080 >>> id(A().a) 54108104 >>> id(A().a) 54107080 >>> id(A().a) 54108104 >>> >>> id(A().a) 54108104 >>> >>> id(A().a) 54108104 >>> id(A().a) 54107080 >>>

The id of the method changes with the parity of the line!

I actually wanted to create a couple of instances of the same class and see if they had the same method object, and I expected that they would be the exact same one, or change every time, what I did not expect was that the method id would be related with the interpreter line being even or not! Any ideas?

Note: I know that there is a mismatch of version from the docs and the interpreter, it just happens that I'm on windows and I have only 3.2 installed

Answer1:

I will explain wat the line id(A().a) does:

A() # creates a new object I call a

Then

A().a # creates a function f bound to a A.a.__get__(A(), A) # same as above >>> A.a.__get__(A(), A) <bound method A.a of <__main__.A object at 0x02D85550>> >>> A().a <bound method A.a of <__main__.A object at 0x02D29410>>

This bound function is always another because it has another object in __self__

>>> a = A() >>> assert a.a.__self__ is a

__self__ will be passed as first argument self to the function A.a

EDIT: This is what it looks like:

Python 3.3.0 (v3.3.0:bd8afb90ebf2, Sep 29 2012, 10:55:48) [MSC v.1600 32 bit (Intel)] on win32 Type "copyright", "credits" or "license()" for more information. >>> class A: def a(self): pass >>> id(A().a) 43476312 >>> id(A().a) 49018760

Here the id repeats like abab

Python 3.2.2 (default, Sep 4 2011, 09:51:08) [MSC v.1500 32 bit (Intel)] on win32 Type "copyright", "credits" or "license()" for more information. >>> class A: def a(self): pas s >>> id(A().a) 50195512 >>> id(A().a) 50195832 >>> id(A().a) 50195512 >>> id(A().a) 50195832

EDIT: For linux or what is not my machine and whatsoever I do not know

id(A().a)

will always give the same result except if you store this to a variable. I do not know why but I would think that it is because of performance optimization. For objects on the stack you do not need to allocate new space for an object every time you call a function.

人吐槽 人点赞

Recommend

Comment

用户名: 密码:
验证码: 匿名发表

你可以使用这些语言

查看评论:Why the id of an object would change depending on the line in the python shell