23511 Reversing a five digit number with POW function in C

I have an exercise which demands a program that reverts a five digit number using pow, here is my try:

#include <math.h> #include <stdio.h> void main( void ) { int number, counter = 0, last_digit, reversed = 0; printf( "Please type a five digit number and I will reverse it\n" ); scanf( "%d", &number ); for( counter = 4; counter >= 0; counter-- ) { last_digit = number % 10; number = number / 10; //printf( "%d %d %.0f %.0f\n\n", reversed, last_digit, pow ( 10, counter ), reversed + last_digit * pow( 10, counter )); reversed = reversed + last_digit * pow( 10, counter ); }//end for printf( "The number reversed is %d", reversed ); }//end main

But if I type 12345 it returns 54320, the last digit is wrong! To check what was going on I enabled the printf comment an here it is a sample of execution:

Please type a five digit number and I will reverse it 12345 0 5 10000 50000 49999 4 1000 53999 53999 3 100 54299 54299 2 10 54319 54319 1 1 54320 The number reversed is 54320

For some reason the first 50000 is converted to 49999, there is one less! And the weird part is that it only happens the first time, then for example 53999 is correctly converted to 53999. What is happening here?